Bonjour, je n'ai pas compris l'exercice n°1 pouvez vous m'aider, merci d'avance.

Bonjour,
1) f(2/3) = -3(2/3) +6
F(2/3) = - 6/9 + 6
= - 6/9 + 54/6
= 48/6
= 7

g(2/3) = 1/2(2/3) + 1
= 2/6 + 1
= 2/6 + 6/6
= 8/6 = 4/3

2) f(x) = -3x + 6 = 0
= -3x = -6
= x = 2
Donc f(2)= 0

g(x) = 1/2x + 1 = 0
1/2 x = -1
X = -2
G(-2)=0

3) jsp
4) tu trace un repère orthogonal